Friday, December 16, 2005

We need to order more Dunce caps!

Holy cow, folks! I am FRIGHTENED. So I logged back onto the brainteaser website from which I found yesterday's puzzle and was reading through some of the answers that other folks submitted. Y'all ...... there are some STUPID people in the world ... just sayin'.

So since I have not done any Craigslist bashing in awhile .... I thought I'd do some Brainteaser Stupid Answer bashing.

Again, please note that none of the following submissions were from any of my 2 or 3 blog readers.

Let me say that again:
none of the following submissions were from my blog readers.

My blog readers are highly intelligent folks. These other people clearly ARE NOT!

Case in point: not only do they submit stupid answers .... but they do so without HAVING to do so. I mean, not solving the puzzle is no big deal. Really. But these folks went out of their way to submit answers. And even proudly signed their names* to what they submitted! WHY??

You'll note that many of them prove that they can't read and comprehend simple instructions (hello? there is NO "7" in between the numbers "1 to 6".)

Others prove they cannot add. At all. And lord knows I'm no math genius. But we're talking basic addition here folks.

So read the following at your own risk. You may become disheartened by the stupidity that abounds. It certainly amazed me!

Those that felt the need to submit an answer stating that they believed there was no answer:

Impossible!
Carlos Q - 13 Dec, 2005

Impossible
vvrmohan - 14 Dec, 2005

there is no possibility
bhanuchander - 16 Dec, 2005

there is no solution to this puzzle. i tried all the combinations with 6 numbers and you will find there is no answer.
arunkumar s - 11 Dec, 2005

this is immmposible:(
vemuri suman c - 11 Dec, 2005

[and my favorite of this group.......]

there is no answer.
DO NOT GIVE SUCH TYPE OF WRONG QUESTIONS.
rajkumar - 15 Dec, 2005 [angry much??]

Those that felt the need to submit a long-winded answer (in an attempt to sound intelligent) as to why they believe there is no answer:

There is no answer.
1 + 5 = 6, but the leftover numbers have no working combinations: 2 + 3 = 5, 2 + 4 = 6, 3 + 4 = 7.
2 + 4 = 6, but again, the leftovers don't work: 1 + 5 = 6, 1 + 3 = 4, 3 + 5 = 8
This occurs no matter where you start off.
Akusu - 11 Dec, 2005

using 6 digits i.e 1,2,3,4,5,6
steps involving the equation balencing
let us assume the balencing equation as
AB(+)CD =EF
Now choose the 'B' values from 1 to 6
if B=1, then D=2, B+D=3=F
Then A=4 , C=5, A+C=9=E in this case AB+CD=EF, 41+52=93!=63, so we can't get the distinct values of A,B,C,D,E,F.
then go for B=1, D=3,B+D=4=F.Then A=2, C=5, A+C=7.in this case digit 7 comes to our sum.
this is not possible since we use 1,2,3,4,5,6.
similarly not Balence if B=1,D=4,B+D=5=F
if B=1,D=5,B+D=6=F
if B=1,D=6,B+D=7=F(not happen this case)
In this case if B=1, we have seen possible values of D=2,3,4,5,6. Even though the equation not balenced.
Simillarly if we take B=2, D=1 or 3 or 4 or 5 or 6 then in this case also we can't get different values of A,B,C,D,E,F satisfying the equation AB+CD=EF
Simillarly if we take B=3,then D=1 or 2 or 4 or 5 or 6. Then in this case also we can't get different values of A,B,C,D,E,F satisfying the equation AB+CD=EF.
Similarly when B=4, then D=1 or 2 or 3 or 5 or 6. Here also we can't get the values satisfying AB+CD=EF.
Similarly when B=5, then D=1 or 2 or 3 or 4 or 6. Here also same as above.
But in last case if B=6, then in this case D=1 or 2 or 3 or 4 or 5. if D=1 then B+D=7 .This is never happens.In This case we never balence.
All possible cases choosing the values of B=1,2,3,4,5,6 we have seen.no one case balenced in the given problem.
Therefore my conclusion is we can't balence in this equation using 1,2,3,4,5,6.
K.N.V.U - 15 Dec, 2005

The balancing of this equation is not possible given the constraints (using the digits 1,2,3,4,5,6).
Reason:
The logic is pretty simple: given the set of numbers (1,2,3,4,5,6) the final result must contain the largest numbers. => 5 and 6
for 6 addition results are 2+4 or 1+5.
But once used either of these 2+4=6 and 1+5=6 it is not possible to get the desired result from the other two sets 1,3,5 or 2,3,4 resectively.
Since the equation can't be proved for number 6 and 6 must be in the result hence this equation can't be logically possible.
D. Chaitanya K - 16 Dec, 2005

This grouping I call "HUH??":

well this problem needs 6 numbers total. so i tried to have the VERY last number be six. so i just basically tried problems to come up with 6 as the last digit and i came up with 64+12=76 [it needs 6 numbers and so you made the last number be “6”??? What does that MEAN, Megan???]
megan - 11 Dec, 2005

Well 1+5=6 right so you have used each of the numbers once!
John - 11 Dec, 2005

first find 2 numbers that = a number 6 or below and the awnser and it will be 2+3=5
jake - 11 Dec, 2005

14 + 25 = 39
Here '9' is made by rotating '6' by 180 [are you KIDDIN’ ME?!! You’re seriously submitting an answer in which you ROTATED a number!!?!!?!!?!!! WTF?!!]
Shamsunder - 14 Dec, 2005

Those that can’t comprehend basic english:

1+2=3
Mohit A - 12 Dec, 2005

3+1=4
Jaclyn - 13 Dec, 2005

14+12=26
Dwight L - 13 Dec, 2005

01+03=04
chad - 14 Dec, 2005

24 + 37 = 61
Rob - 15 Dec, 2005

-21+53=32
ravi - 15 Dec, 2005

cause 11+11=22 and all them numbes are two digit and are between 1-6
retta - 15 Dec, 2005

11+15=26
TANGUTURI.R- 16 Dec, 2005

12+34=46
harika - 13 Dec, 2005


12+34+56= if i can only use each number only once why not this answer?
billy - 15 Dec, 2005 [uhhh, maybe because your answer makes ABSOLUTELY NO SENSE. AND it’s not following the guidelines of the puzzle. Sigh]

you can put 5+1=6.
mary loo - 11 Dec, 2005

48+23=71
chad - 14 Dec, 2005


61+16=77 [two 6’s, two 1’s and not one but two 7’s. By jove, Kia, I think you’ve got it!]
Kia - 11 Dec, 2005

12 plus 53 equals 65. No steps were taken, but i knew that the answer was most likely high number. I tried some numbers and they were right..lucky guess
Amanda - 14 Dec, 2005 [yes, very lucky guess. You should definitely go forth and procreate.]


From those who felt the need to explain their stupid:

the teacher writes an equation on the board he then tells the students to write two numbers on each line and they can only use 1-6 only once. so if you only use 1-6 once you would have come up with 12+34=56. see you only use each number one time and the answer is correct. [Brandy, please tell me that you’re still under 10 years old. Cuz uh …. 12+34 <> 56 in my world]
brandy - 11 Dec, 2005

2+3=5 i dont have an explanation because i just though of this off the top of my head!
sherri - 13 Dec, 2005 [appreciate the effort there, Sherri. Nice of you to stop by. Move along]

12 + 46 = 58
It was easy actually.
The Adding up digits could be anywhere between 12- 53 . 12 becuase it had to be greater than 9 being 2 digit. I could not be 10 because adding anything to 10 gives you the same digit in the unit place. could not be 11 because it has repetation of digits.
Same way , you realize that the Addition could be anywhere between 46 - 65.
In this case, adding both the lower limits gave the answer. There might be other solutions also, but I did not really check.
Akash J - 11 Dec, 2005 [sigh]

Assuming the equation is ab + cd = ef, as all the digits have to be unique and ranging from 1 to 6.
I guess the equation cannot be satisfied by whole numbers because only e or f can be the digit 6. and even if either of them is 6 then one of the other digits gets repeated.
Now if we think of using decimal point numbers then, I guess there is only one solution as follows:
1.6 + 3.4 = 5.0,
where one should consider 5.0 as two digits but disregard the 0 in 5.0 as it is after the decimal point.
Aysha S - 14 Dec, 2005

And last but not least, those from folks who simply can't add (only a sampling ... too many to list):

21 + 34 = 65 or 12 + 43 = 56
numbers used are only from 1 to 6
shivu - 15 Dec, 2005 [perfect, Shivu! You’ve proven your brilliance not once but TWICE!!!]

21+43=65
Meenakshi - 11 Dec, 2005

13+42=65
P V S A - 16 Dec, 2005

21 + 43 = 65
maddy - 10 Dec, 2005

23+45=61
bmcgee - 15 Dec, 2005

well, it seems to me that the number
12 + 34 = 56. simple
Ryan - 15 Dec, 2005 [well sure, simple for you, Ryan. Because you’re a genius! But not everyone can be a member of Mensduh …. Errr, I mean, Mensa!]


And there you have it, folks. People who are out and about loose in our society. Now isn't that a comforting thought?? :)

*please note that I have removed the last names to protect the ....errr ... well, to protect them from themselves. Many proudly displayed both first and last name on the other site. (*head shake*)

3 comments:

d said...

I still don't see AN ANSWER!

Sis said...

Don't put the answer yet because even though I am math challenged I am going to figure it out. Where is that damn calculator?

Anonymous said...

SPOILER ALERT!
Maybe I'm confused here but I got 24 + 32 = 56. But I got it relatively quickly so maybe I missed something? I solved it by falling back on my genious method that I perfected back when I worked hard at failing math - 'guess and test.' Does this earn me a place on the wall of shame? I'm guessing a lot of those folks converting it to letters, etc. are too smart for their own good? Anyhow, what's the answer??? --RR in PDX